Let a be an integer such that _ x 7 (18 − [1 − x])/([x − 3a]) exists, where [t] is greatest integer t. Then a is equal to :

JEE Main 2022 Mathematics question

Let a be an integer such that (18 − [1 − x])/([x − 3a]) exists, where [t] is greatest integer . Then a is equal to :

Answer: (1)

As , [1 − x] = −7 and [x − 3a] = 7 − 3a (a an integer), so the limit from the right is (18 + 7)/(7 − 3a) = 25/(7 − 3a). As , [1 − x]

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Question ID VK-034600