JEE Main 2022 Mathematics question
Let the mirror image of the point (a, b, c) with respect to the plane 3x − 4y + 12z + 19 = 0 be (a − 6, , ). If a + b + c = 5, then is equal to .
Answer: 137
Solution
The image (x, y, z) of (a, b, c) satisfies (x − a)/3 = (y − b)/(−4) = (z − c)/12 = −2(3a − 4b + 12c + 19)/169. For x = a − 6: −6/3 = −2, so 3a − 4b + 12c + 19 = 169, i.e. 3a − 4b + 12c = 150. Then $β = b +
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account