JEE Main 2022 Physics question
Assume there are two identical simple pendulum clocks. Clock – 1 is placed on the earth and Clock - 2 is placed on a space station located at a height h above the earth surface. Clock – 1 and Clock - 2 operate at time periods 4 s and 6 s respectively. Then the value of h is- (consider radius of earth = 6400 km and g on earth 10 )
Answer: (3)
Solution
, so = R/(R + h) (since $g
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account