Let y = y(x) be the solution curve of the differential equation dy/dx + (1/(x^ 2 - 1))y = ((x − 1)/(x + 1))^ 1/2 , x > 1 passing through the point (2, 1/3 ). Then 7 y(8) is

JEE Main 2022 Mathematics question

Let y = y(x) be the solution curve of the differential equation dy/dx + ( − 1)/(x + , x > 1 passing through the point (2, ). Then y(8) is

Answer: (4)

The integrating factor is − 1)} = = − 1)/(x + 1)). So − 1)/(x + − 1)/(x + − 2/(x + 1))dx = x − 2ln|x + 1|

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Question ID VK-034696