Let S_ 1 = z_ 1 C : |z_ 1 − 3| = 1/2 and S_ 2 = z_ 2 C : |z_ 2 - |z_ 2 + 1|| = |z_ 2 + |z_ 2 − 1|| . Then, for z_ 1 S_ 1 and z_ 2 S_ 2 , the least value of |z_ 2 - z_ 1 | is :

JEE Main 2022 Mathematics question

Let C : − 3| = 1/2} and C : + 1|| = − 1||}. Then, for and , the least value of is :

Answer: (C)

Squaring the condition of and simplifying gives ( + 1| + − 1| − 2) = 0. So either lies on the imaginary axis) or + 1| + − 1| = 2 ( lies on the

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Question ID VK-034790