JEE Main 2022 Physics question
A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm, 1.23 mm, 1.19 mm and 1.20 mm. The percentage error is x/121 %. The Value of x is .
Answer: 150
Solution
The mean is (1.22 + 1.23 + 1.19 + 1.20)/4 = 1.21 mm. The absolute errors are 0.01, 0.02, 0.02 and
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account