JEE Main 2022 Chemistry question
For combustion of one mole of magnesium in an open container at 300 K and 1 bar pressure, = −601.70 kJ , the magnitude of change in internal energy for the reaction is kJ. (Nearest integer) (Given : R = 8.3 J )
Answer: 600
Solution
, so = −1/2. gives −601.70 =
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