If one of the diameters of the circle x^ 2 + y^ 2 - 2 2x - 6 2y + 14 = 0 is a chord of the circle (x - 2 2 )^ 2 + (y - 2 2 )^ 2 = r^ 2 , then the value of r^ 2 is equal to _____ .

JEE Main 2022 Mathematics question

If one of the diameters of the circle is a chord of the circle , then the value of is equal to .

Answer: 10

The first circle has centre , ) and radius , so its diameter has length . The second circle has centre , ), and $ = {( +

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Question ID VK-034888