JEE Main 2022 Chemistry question
A 2.0 g sample containing is treated with HCl liberating . The gas is passed into a solution of KI and 60.0 mL of 0.1 M is required to titrate the liberated iodine. The percentage of in the sample is . (Nearest integer) [Atomic masses (in u) Mn = 55; Cl = 35.5; O = 16; I = 127, Na = 23, K = 39, S = 32]
Answer: 13
Solution
MnO_{2} + 4HCl \to MnCl_{2} + 2H_{2}O + Cl_{2}; ; . So 1 mol ≡ 1 mol ≡ 1 mol
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account