If the system of linear equations 2x + 3y − z = −2, x + y + z = 4, x - y + | |z = 4 - 4 where R, has no solution, then

JEE Main 2022 Mathematics question

If the system of linear equations 2x + 3y − z = −2, x + y + z = 4, where R, has no solution, then

(1)
(2) = −7Correct
(3)
(4)

Answer: (2)

Solution

The coefficient determinant |2 3 −1; 1 1 1; 1 −1 gives . The third equation is then , and gives 5(x + y + z) − 2(2x + 3y − z) = x − y + 7z = 20 + 4 = 24. For

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-034958