JEE Main 2022 Physics question
A circuit element X when connected to an a.c. supply of peak voltage 100 V gives a peak current of 5 A which is in phase with the voltage. A second element Y when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by . If X and Y are connected in series to the same supply, what will be the rms value of the current in ampere ?
Answer: (4)
Solution
X is a resistor with R = 100/5 = 20 , and Y is an inductor with = 20 (the current lags the voltage by ). In series $Z
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account