Consider the reaction 4HNO_ 3 ( ) + 3KCl(s) Cl_ 2 (g) + NOCl(g) + 2H_ 2 O(g) + 3KNO_ 3 (s) The amount of HNO_ 3 required to produce 110.0 g of KNO_ 3 is : (Given : Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.)

JEE Main 2022 Chemistry question

Consider the reaction 4HNO_{3}(\ell ) + 3KCl(s) \to Cl_{2}(g) + NOCl(g) + 2H_{2}O(g) + 3KNO_{3}(s) The amount of required to produce 110.0 g of is : (Given : Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.)

(1)32.2 g
(2)69.4 g
(3)91.5 gCorrect
(4)162.5 g

Answer: (3)

Solution

The molar mass of is 101 g/mol, so 110 g is 110/101 mol. From the reaction, 4 mol gives 3 mol

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Question ID VK-035016