JEE Main 2022 Chemistry question
For a cell, Cu(s)|Cu^{2+}(0.001M)||Ag^{+}(0.01M)|Ag(s) the cell potential is found to be 0.43 V at 298 K. The magnitude of standard electrode potential for is V. [Given : V and 2.303RT/F = 0.06 V]
Answer: 34
Solution
The cell reaction is Cu + 2Ag^{+} \to Cu^{2+} + 2Ag. = E°_cell − : 0.43 = E°_cell − 0.03 = E°_cell − 0.03
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