If the solubility product of PbS is 8 10^ -28 , then the solubility of PbS in pure water at 298 K is x 10^ -16 mol L^ -1 . The value of x is _____. (Nearest Integer) [Given 2 = 1.41]

JEE Main 2022 Chemistry question

If the solubility product of PbS is , then the solubility of PbS in pure water at 298 K is mol . The value of x is . (Nearest Integer) [Given ]

Answer: 282

= , so \sqrt{8 × 10^{-28}}\sqrt{2}$ ×

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Question ID VK-035131