JEE Main 2022 Mathematics question
Let a line with direction ratios a, −4a, −7 be perpendicular to the lines with direction ratios 3, −1, 2b and b, a, −2. If the point of intersection of the line = z/1 and the plane x − y + z = 0 is (, , ), then is equal to .
Answer: 10
Solution
(a, −4a, −7) (3, −1, 2b): 3a + 4a − 14b = 0, so a = 2b. (a, −4a, −7) (b, a, −2): ab − . Substituting a = 2b: , so and . The line is (x + 1)/5
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