JEE Main 2022 Physics question
The vernier constant of Vernier callipers is 0.1 mm and it has zero error of (−0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be cm.
Answer: 180
Solution
Since the zero error is negative, 0.05 cm is added. The corrected reading is 1.7 cm +
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