JEE Main 2022 Mathematics question

MathematicsDifferential EquationJEE Main 2022

Let y = y(x), x > 1, be the solution of the differential equation (x − 1)dy/dx + 2xy = 1/(x − 1), with . If , then the value of is equal to .

Answer: 14

Solution

Dividing by (x − 1): dy/dx + (2x/(x − 1))y = 1/(x − . The integrating factor is Extra open brace or missing close bracee^{\int 2x dx/(x − 1)} = Extra open brace or missing close bracee^{\int (2 + 2/(x − 1))dx} = = − . Then d(y − ) = , so y −

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Question ID VK-035247