JEE Main 2022 Mathematics question
Let y = y(x), x > 1, be the solution of the differential equation (x − 1)dy/dx + 2xy = 1/(x − 1), with . If , then the value of is equal to .
Answer: 14
Solution
Dividing by (x − 1): dy/dx + (2x/(x − 1))y = 1/(x − . The integrating factor is dx/(x − 1)} = + 2/(x − 1))dx} = = − . Then d(y − ) = , so y −
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