A particle of mass 500 gm is moving in a straight line with velocity v = bx^ 5/2 . The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m^ -3/2 s^ -1 ).

JEE Main 2022 Physics question

A particle of mass 500 gm is moving in a straight line with velocity v = . The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 ).

(1)2 J
(2)4 J
(3)8 J
(4)16 JCorrect

Answer: (4)

Solution

By the work–energy theorem . At x = 4 m, $v = 0.25

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Question ID VK-035263