JEE Main 2022 Physics question

A parallel plate capacitor filled with a medium of dielectric constant 10, is connected across a battery and is charged. The dielectric slab is replaced by another slab of dielectric constant 15. Then the energy of capacitor will -

(1)increased by 50%Correct
(2)decrease by 15%
(3)increase by 25%
(4)increase by 33%

Answer: (1)

Solution

The battery keeps the potential difference V constant, so the energy is $U =

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Question ID VK-035272