JEE Main 2022 Physics question
300 cal. of heat is given to a heat engine and it rejects 225 cal. of heat. If source temperature is 227°C, then the temperature of sink will be °C.
Answer: 102
Solution
The efficiency is − 225)/300 = 1/4 = 1 − /, with = 227 + 273 = 500 K. So = (3/4)(500) = 375 K = 102°C.