JEE Main 2022 Chemistry question
Production of iron in blast furnace follows the following equation Fe_{3}O_{4}(s) + 4CO(g) \to 3Fe(l) + 4CO_{2}(g) when 4.640 kg of and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is: [Given : Molar Atomic mass (g ) : Fe = 56, Molar Atomic mass (g ) : O = 16, Molar Atomic mass (g ) : C = 12]
Answer: (3)
Solution
The moles are mol and n(CO) = 2520/28 = 90 mol. needs
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