JEE Main 2022 Chemistry question
The number of terminal oxygen atoms present in the product B obtained from the following reaction is . FeCr_{2}O_{4} + Na_{2}CO_{3} + O_{2} \to A + Fe_{2}O_{3} + CO_{2}
Answer: 6
Solution
Chromite ore fuses with sodium carbonate in air to give sodium chromate: 4FeCr_{2}O_{4} + 8Na_{2}CO_{3} + 7O_{2} \to 8Na_{2}CrO_{4} (A) + 2Fe_{2}O_{3} + 8CO_{2}.
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