Let the solution curve of the differential equation x dy/dx − y = y^ 2 + 16x^ 2 , y(1) = 3 be y = y(x). Then y(2) is equal to :

JEE Main 2022 Mathematics question

Let the solution curve of the differential equation x dy/dx − , y(1) = 3 be y = y(x). Then y(2) is equal to :

Answer: (1)

Put y = xv, so and the right side is . So , i.e. = dx/x. Integrating, = ln x + C. With y(1) =

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Question ID VK-035317