JEE Advanced 2025 Mathematics question
Consider the vectors
x = i + 2 j + 3 k, y = 2 i + 3 j + k, and z = 3 i + j + 2 k.
For two distinct positive real numbers α and β, define
X = α x + β y - z, Y = α y + β z - x, and Z = α z + β x - y.
If the vectors , , and lie in a plane, then the value of α + β − 3 is .
Answer: -2
Solution
, and \vec\vec\vec\begin{vmatrix} 1 & 2 & 3 \\ 2 & 3 & 1 \\ 3 & 1 & 2 \end{vmatrix}$ = -18
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Question ID VK-035477