JEE Advanced 2025 Chemistry question
At 300 K, an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height (h) of the solution (density = 1.00 g cm⁻³) where h is equal to 2.00 cm. If the concentration of the dilute solution of the macromolecule is 2.00 g dm⁻³, the molar mass of the macromolecule is calculated to be g mol⁻¹. The value of X is . Use: Universal gas constant (R) = 8.3 J K⁻¹ mol⁻¹ and acceleration due to gravity (g) = 10 m s⁻²
Answer: 2.49
Solution
π = hρg = 0.0200 m × 1000 kg m⁻³ × 10 m s⁻² = 200 Pa. Concentration 2.00 g dm⁻³ = 2.00 kg m⁻³. From π = (c/M)RT:
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