JEE Main 2023 Chemistry question
FeO_4^{2-}\xrightarrow{+2.2V}Fe^{3+}\xrightarrow{+0.70V}Fe^{2+}\xrightarrow{-0.45V}Fe^0 is xV. The value of x is .
Answer: 1825
FeO_4^{2-}\xrightarrow{+2.2V}Fe^{3+}\xrightarrow{+0.70V}Fe^{2+}\xrightarrow{-0.45V}Fe^0 is xV. The value of x is .