JEE Main 2023 Mathematics question
If \frac{1}{n+1}{}^nC_n+\frac{1}{n}{}^nC_{n-1}+\ldots+\frac{1}{2}{}^nC_1+{}^nC_0=\frac{1023}{10} then n is equal to
Answer: (A)
If \frac{1}{n+1}{}^nC_n+\frac{1}{n}{}^nC_{n-1}+\ldots+\frac{1}{2}{}^nC_1+{}^nC_0=\frac{1023}{10} then n is equal to