Let y = y(x), y > 0, be a solution curve of the differential equation (1+x^2)dy=y(x-y)dx. If y(0) = 1 and y(2 2)= , then

JEE Main 2023 Mathematics question

Let y = y(x), y > 0, be a solution curve of the differential equation . If y(0) = 1 and y, then

Answer: (A)

Question ID VK-036159