JEE Main 2023 Chemistry question
20 mL of 0.1 M NaOH is added to 50 mL of 0.1 M acetic acid solution. The pH of the resulting solution is . (Nearest integer) Given : = 4.76 log 2 = 0.30 log 3 = 0.48
Answer: 458
20 mL of 0.1 M NaOH is added to 50 mL of 0.1 M acetic acid solution. The pH of the resulting solution is . (Nearest integer) Given : = 4.76 log 2 = 0.30 log 3 = 0.48