JEE Main 2023 Physics question

PhysicsOscillationsJEE Main 2023

At a given point of time the value of displacement of a simple harmonic oscillator is given as y = A cos(30°). If amplitude is 40 cm and kinetic energy at that time is 200 J, the value of force constant is . The value of x is .

Answer: 4

Solution

Question ID VK-036377