JEE Main 2023 Mathematics question
Let the system of linear equations x + y + kz = 2, 2x + 3y – z = 1, 3x + 4y + 2z = k have infinitely many solutions. Then the system (k+1)x + 2(k–1)y = 7, (2k+1)x + (k+5)y = 10 has :
Answer: (A)
Let the system of linear equations x + y + kz = 2, 2x + 3y – z = 1, 3x + 4y + 2z = k have infinitely many solutions. Then the system (k+1)x + 2(k–1)y = 7, (2k+1)x + (k+5)y = 10 has :