JEE Main 2023 Physics question

Two parallel plate capacitors and each having capacitance of 10 F are individually charged by a 100 V D.C. source. Capacitor is kept connected to the source and a dielectric slab is inserted between its plates. Capacitor is disconnected from the source and then a dielectric slab is inserted in it. Afterwards the capacitor is also disconnected from the source and the two capacitors are finally connected in parallel combination. The common potential of the combination will beV. (Assuming Dielectric constant = 10)