JEE Advanced 2007 Mathematics question

MathematicsApplication of DerivativesJEE Advanced 2007

Let f(x) = 2 + cos x for all real x. STATEMENT-1 : For each real t, there exists a point c in [t, t + π] such that f′(c) = 0. because STATEMENT-2 : f(t) = f(t + 2π) for each real t.

Answer: (B)

Solution

at x = kπ. Every closed interval of length π, [t, t + π], contains a multiple of π, so Statement-1 is true. Statement-2: cos x has

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-037525