JEE Advanced 2008 Chemistry question

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of gas at the cathode is (1 Faraday = 96500 C mol⁻¹)

(A) sec
(B) secCorrect
(C) sec
(D) sec

Answer: (B)

Solution

: 0.01 mol needs 0.02 mol electrons = 0.02 ×

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Question ID VK-037655