JEE Advanced 2009 Mathematics question

Tangents drawn from the point P(1, 8) to the circle

+ - 6x - 4y - 11 = 0

touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is

Answer: (B)

Solution

The centre of the given circle is C(3, 2). The radii CA and CB are perpendicular to the tangents PA and PB, so A and B lie on the circle with

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Question ID VK-037692