A block of base 10 cm × 10 cm and height 15 cm is kept on an inclined plane. The coefficient of friction between them is 3 . The inclination θ of this inclined plane from the horizontal plane is gradually increased from 0°. Then

JEE Advanced 2009 Physics question

Physics Laws of Motion JEE Advanced 2009

A block of base 10 cm × 10 cm and height 15 cm is kept on an inclined plane. The coefficient of friction between them is . The inclination θ of this inclined plane from the horizontal plane is gradually increased from 0°. Then

(A)at θ = 30°, the block will start sliding down the plane
(B)the block will remain at rest on the plane up to certain θ and then it will toppleCorrect
(C)at θ = 60°, the block will start sliding down the plane and continue to do so at higher angles
(D)at θ = 60°, the block will start sliding down the plane and on further increasing θ, it will topple at certain θ

Answer: (B)

Solution

Sliding would begin when tan θ = μ = √3, i.e. θ = 60°. Toppling occurs when the vertical through the centre of mass passes the lower edge: tan θ = (half

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Question ID VK-037712