The correct stability order of the following resonance structures is H_2C = + N = - N (I) H_2 + C - N = - N (II) H_2 - C - + N N (III) H_2 - C - N = + N (IV)

JEE Advanced 2009 Chemistry question

The correct stability order of the following resonance structures is (I) (II) (III) (IV)

(A)(I) > (II) > (IV) > (III)
(B)(I) > (III) > (II) > (IV)Correct
(C)(II) > (I) > (III) > (IV)
(D)(III) > (I) > (IV) > (II)

Answer: (B)

Solution

(I) and (III) give every atom an octet; (I) puts the negative charge on the more electronegative terminal nitrogen, so it is the most stable, followed by (III) (negative charge on carbon). (II) has a carbon with

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Question ID VK-037734