JEE Advanced 2009 Chemistry question
In a constant volume calorimeter, 3.5 g of a gas with molecular weight 28 was burnt in excess oxygen at 298.0 K. The temperature of the calorimeter was found to increase from 298.0 K to 298.45 K due to the combustion process. Given that the heat capacity of the calorimeter is 2.5 kJ K⁻¹, the numerical value for the enthalpy of combustion of the gas in kJ mol⁻¹ is
Answer: 9
Solution
Heat released = kJ. Moles of gas mol. Heat released per mole kJ mol⁻¹, so the
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