JEE Advanced 2009 Mathematics question
Let ABC and ABC′ be two non-congruent triangles with sides AB = 4, and angle B = 30°. The absolute value of the difference between the areas of these triangles is
Answer: 4
Solution
With c = AB = 4, b = AC = 2√2 and B = 30°, the cosine rule gives a^2\sqrta^2\sqrt$3a +
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