JEE Advanced 2009 Mathematics question

MathematicsSolution of TrianglesJEE Advanced 2009

Let ABC and ABC′ be two non-congruent triangles with sides AB = 4, and angle B = 30°. The absolute value of the difference between the areas of these triangles is

Answer: 4

Solution

With c = AB = 4, b = AC = 2√2 and B = 30°, the cosine rule gives a^2\sqrta^2\sqrt$3a +

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Question ID VK-037763