JEE Advanced 2009 Physics question
A 20 cm long string, having a mass of 1.0 g, is fixed at both the ends. The tension in the string is 0.5 N. The string is set into vibrations using an external vibrator of frequency 100 Hz. Find the separation (in cm) between the successive nodes on the string.
Answer: 5
Solution
Linear density kg/m; wave speed
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account