JEE Advanced 2025 Physics question

PhysicsLaws of MotionJEE Advanced 2025

A person sitting inside an elevator performs a weighing experiment with an object of mass 50 kg. Suppose that the variation of the height y (in m) of the elevator, from the ground, with time t (in s) is given by , where T = 40π s. Taking acceleration due to gravity, g = 10 m/s², the maximum variation of the object's weight (in N) as observed in the experiment is

Answer: 2

Solution

, with s⁻¹, so $|a|_{max} =

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-037811