JEE Advanced 2025 Physics question

PhysicsUnits and MeasurementJEE Advanced 2025

A single slit diffraction experiment is performed to determine the slit width using the equation, , where b is the slit width, D the shortest distance between the slit and the screen, d the distance between the diffraction maximum and the central maximum, and λ is the wavelength. D and d are measured with scales of least count of 1 cm and 1 mm, respectively. The values of λ and m are known precisely to be 600 nm and 3, respectively. The absolute error (in µm) in the value of b estimated using the diffraction maximum that occurs for m = 3 with d = 5 mm and D = 1 m is

Answer: 75.6

Solution

m = 360 µm. Relative error $ =

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Question ID VK-037815