JEE Main 2002 Physics question
Two forces are such that the sum of their magnitudes is 18 N and their resultant is 12 N which is perpendicular to the smaller force. Then the magnitudes of the forces are
Answer: (2)
Solution
Let the smaller force be and the larger be , so . Since the resultant N is perpendicular to , the vectors , and form a right triangle with as the hypotenuse: . Factorising, $(Q-P)(Q+P) = 144 ⇒
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