JEE Main 2002 Physics question
A tuning fork arrangement (pair) produces 4 beats / sec with one fork of frequency 288cps. A little wax is placed on the unknown fork and it then produces 2 beats /sec. The frequency of the unknown fork is
Answer: (2)
Solution
With 4 beats/s, the unknown frequency is , i.e. 292 or 284 cps. Loading with wax lowers the frequency of the unknown fork. If it were 292, lowering it moves it towards 288, so beats decrease (to 2 beats/s when it becomes 290) —
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