JEE Main 2002 Chemistry question

On vigorous oxidation by permanganate solution (CH_3)_2C = CH - CH_2 - CHO gives

(1)
(2)\left.\begin{matrix}CH_3\\CH_3\end{matrix}\right\rangle COOH + CH_3CH_2COOHCorrect
(3)\left.\begin{matrix}CH_3\\CH_3\end{matrix}\right\rangle CH-OH + CH_2CH_2CH_2OH
(4)\left.\begin{matrix}CH_3\\CH_3\end{matrix}\right\rangle C=O + CH_3CH_2CHO

Answer: (2)

Solution

Hot, concentrated (vigorous) cleaves the C=C bond: the end becomes acetone , and the end is oxidised to a carboxylic acid; the –CHO group is also oxidised to –COOH, giving malonic acid . Among the printed options, only (2) shows the

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Question ID VK-037980