The centre of the circle passing through (0, 0) and (1, 0) and touching the circle x^2 + y^2 = 9 is

JEE Main 2002 Mathematics question

The centre of the circle passing through and and touching the circle is

(1)
(2)Correct
(3)
(4)

Answer: (2)

Solution

The centre lies on the perpendicular bisector of (0, 0) and (1, 0), so it is with radius . The circle passes through the origin, which is inside , so it touches internally: distance between centres . That distance is

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Question ID VK-038019