JEE Main 2003 Physics question
A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground?
[g = 10\ m/, 30° = , 30° = ]
Answer: (4)
Solution
A height of 10 m above the ground is the level of the roof, i.e. the level of projection. The ball returns to this level after covering the horizontal range \frac{u^2\sin2θ}{g}$ =
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