JEE Main 2003 Physics question
The work done in placing a charge of coulomb on a condenser of capacity 100 micro-farad is
Answer: (4)
Solution
\frac{q^2}{2C}\frac{(8×10^{-18})^2}{2×100×10^{-6}}\frac{64×10^{-36}}{2×10^{-4}}$ =
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