JEE Main 2003 Physics question
When the current changes from +2 A to −2 A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is
Answer: (4)
Solution
\frac{Δ I}{Δ t}\frac{4}{0.05}$ = 80L ⇒ L =
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