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JEE Main 2003 Physics question

PhysicsNucleiJEE Main 2003

A radioactive sample at any instant has its disintegration rate 5000 disintegrations per minute. After 5 minutes, the rate is 1250 disintegrations per minute. Then, the decay constant (per minute) is

Answer: (1)

Solution

The activity falls from 5000 to 1250, i.e. to , which is two half-lives. So min min and \frac{\ln2}{T_{1/2}}$ =

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Question ID VK-038133